   Chapter 5.3, Problem 55E ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343

#### Solutions

Chapter
Section ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343
Textbook Problem

# What is wrong with the equation? ∫ − 2 1 x − 4 d x = x − 3 − 3 ] − 2 1 = − 3 8

To determine

To check: The given equation 21x4dx=x33]=38, whether it is wrong or right.

Explanation

Given information:

The function is 21x4dx=x33]=38 (1)

The theorem of fundamental calculus part 2 is shown below:

abf(x)dx=F(b)F(a) (2)

Here, F is an antiderivative of f and it is expressed as F'=f.

Rearrange Equation (1) as shown below.

abF(x)dx=F(b)F(a)

Apply the theorem, to analyze the function is continuous in the interval [2,1]:

Substitute x=2 in Equation (1) as shown below.

21x4dx=x33=(2)33=2

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