   Chapter 5.3, Problem 7CP ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Checkpoint 7 Worked-out solution available at LarsonAppliedCalculus.comFind each indefinite integral. ∫ 4 x 2 + 3 x + 2 x 2 d x b. ∫ 2 e − x + 1 d x c. ∫ x 2 + 2 x + 4 x + 1 d x

(a)

To determine

To calculate: The indefinite integral 4x23x+2x2dx.

Explanation

Given Information:

The provided indefinite integral is 4x23x+2x2dx.

Formula used:

The integrals of power function:

xndx=xn+1n+1+C

The integrals of natural logarithmic:

dxx=ln|x|+C

Calculation:

Consider the indefinite integral:

4x23x+2x2dx

Rewrite the integrand as the sum of three fractions:

4x23x+2x2dx=(43x+2x2)dx=(43x+2x2)<

(b)

To determine

To calculate: The indefinite integral 2ex+1dx.

(c)

To determine

To calculate: The indefinite integral x2+2x+4x+1dx.

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