# use part 1 of the fundamental theorem of calculus to find the derivative of the function.

### Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

### Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

#### Solutions

Chapter 5.4, Problem 11E
To determine

## To find: use part 1 of the fundamental theorem of calculus to find the derivative of the function.

Expert Solution

The derivative of the function is F(x)=-1+sec x .

### Explanation of Solution

Given information: The function is F(x)=xπ1+sec t dt

Let’s remind of the fundamental theorem of calculus part 1:

The fundamental theorem of calculus part 1: If f is continuous on [a,b] then the function of g defined by

g(x)=axf(t) dt where axb is continuous on [a,b] and differentiable on (a,b) and g(x)=f(x) .

First, we will use the properties of definite integral to match the form in fundamental theorem of calculus part 1.

So, xπ1+sec t dt= -πx1+sec t dt where F(t)=-F(t)

Hence,

F(x)=-πx1+sec t dt

Now given, F(x)=-πx1+sec t dt

Differentiation with respect to x,

d F(x)dx=ddx[πx1+sec t dt]

F(x)=-1+sec x [ [ where g(x)=f(x)]

Thus, F(x)=-1+sec x

Hence, The derivative of the function is F(x)=-1+sec x .

### Have a homework question?

Subscribe to bartleby learn! Ask subject matter experts 30 homework questions each month. Plus, you’ll have access to millions of step-by-step textbook answers!