   Chapter 5.4, Problem 27E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Evaluating a Definite Integral In Exercises 17-38, evaluate the definite integral. See Examples 3 and 4. ∫ − 1 0 ( t 1 / 3 − t 2 / 3 ) d t

To determine

To calculate: The value of definite integral 10(t1/3t2/3)dt.

Explanation

Given Information:

The integral is 10(t1/3t2/3)dt.

Formula used:

The fundamental theorem of calculus states that,

If f is integrable on interval [a,b] then abf(x)dx=F(b)F(a).

The integration formula is xndx=xn+1n+1+C.

Calculation:

Consider the integral,

10(t1/3t2/3)dt

First find antiderivative by applying the integration formula,

10(t1/3t2/3)dt=[(t4/34/3t5/35/3)]10

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