   Chapter 5.4, Problem 3CP ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# Checkpoint 3 Worked-out solution available at LarsonAppliedCalculus.comEvaluate ∫ 0 1 ( 2 t + 3 ) 3   d t .

To determine

To calculate: The value of definite integral 01(2t+3)3dt.

Explanation

Given Information:

The integral is 01(2t+3)3dt.

Formula used:

The fundamental theorem of calculus states that,

If f is integrable on interval [a,b] then abf(x)dx=F(b)F(a).

The integration formula is xndx=xn+1n+1+C.

Calculation:

Consider the integral,

01(2t+3)3dt

Multiply and divide by 2,

01(2t+3)3(2)dt2

First find antiderivative by applying the integration formula,

01(2t+3)3(2)dt<

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Convert the expressions in Exercises 6584 to power form. x3

Finite Mathematics and Applied Calculus (MindTap Course List)

#### In problems 11-16, write in radical form.Do not simplify. 16.

Mathematical Applications for the Management, Life, and Social Sciences

#### Change 1.5 m3 to cm3.

Elementary Technical Mathematics

#### True or False: converges.

Study Guide for Stewart's Multivariable Calculus, 8th

#### True or False: f(x) = x2 is decreasing for 10 x 1.

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th 