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Math
AlgebraIntermediate Algebra10th Edition

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Chapter 5.4, Problem 59PS
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Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
ISBN: 9781285195728

Solutions

Chapter
Section
Problem 1CQ
Problem 2CQ
Problem 3CQ
Problem 4CQ
Problem 5CQ
Problem 6CQ
Problem 7CQ
Problem 8CQ
Problem 9CQ
Problem 10CQ
Problem 1PS
Problem 2PS
Problem 3PS
Problem 4PS
Problem 5PS
Problem 6PS
Problem 7PS
Problem 8PS
Problem 9PS
Problem 10PS
Problem 11PS
Problem 12PS
Problem 13PS
Problem 14PS
Problem 15PS
Problem 16PS
Problem 17PS
Problem 18PS
Problem 19PS
Problem 20PS
Problem 21PS
Problem 22PS
Problem 23PS
Problem 24PS
Problem 25PS
Problem 26PS
Problem 27PS
Problem 28PS
Problem 29PS
Problem 30PS
Problem 31PS
Problem 32PS
Problem 33PS
Problem 34PS
Problem 35PS
Problem 36PS
Problem 37PS
Problem 38PS
Problem 39PS
Problem 40PS
Problem 41PS
Problem 42PS
Problem 43PS
Problem 44PS
Problem 45PS
Problem 46PS
Problem 47PS
Problem 48PS
Problem 49PS
Problem 50PS
Problem 51PS
Problem 52PS
Problem 53PS
Problem 54PS
Problem 55PS
Problem 56PS
Problem 57PS
Problem 58PS
Problem 59PS
Problem 60PS
Problem 61PS
Problem 62PS
Problem 63PS
Problem 64PS
Problem 65PS
Problem 66PS
Problem 67PS
Problem 68PS
Problem 69PS
Problem 70PS
Problem 71PS
Problem 72PS
Problem 73PS
Problem 74PS
Problem 75PS
Problem 76PS
Problem 77PS
Problem 78PS
Problem 79PS
Problem 80PS
BuyFindarrow_forward

Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
ISBN: 9781285195728
Textbook Problem

For Problems 53-76, rationalize the denominator and simplify. All variables represent positive real numbers. (Objective 3)

2 10 - 3

To determine

To rationalize:

The denominator of the given expression 210-3 and simplify the answer as possible.

Explanation

Given radical is,

210-3.

In order to rationalize the binomial denominator:

An expression which contains a binomial denominator with radical, is multiplied by the conjugate of the binomial denominator.

Here, the factors a+b and a-b are called conjugate.

The denominator of the given expression = 10-3

Conjugate of the given denominator = 10+3

Hence, the numerator and denominator of the given expression is multiplied by 10+3 as below,

210-3=210-3·10+310+3

Simplify the above expression,

210-3=210+310-310+3

210-3=210+2310-310+3

Simplify 10-310+3 as below,

10-310+3=1010+3-3(10+3)

10+310-3=1010+103-310-3

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Chapter 5.4,
Problem 58PS
Chapter 5.4,
Problem 60PS
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Chapter 5 Solutions

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Sect-5.1 P-1CQSect-5.1 P-2CQSect-5.1 P-3CQSect-5.1 P-4CQSect-5.1 P-5CQSect-5.1 P-6CQSect-5.1 P-7CQSect-5.1 P-8CQSect-5.1 P-9CQSect-5.1 P-10CQ
Sect-5.1 P-1PSSect-5.1 P-2PSSect-5.1 P-3PSSect-5.1 P-4PSSect-5.1 P-5PSSect-5.1 P-6PSSect-5.1 P-7PSSect-5.1 P-8PSSect-5.1 P-9PSSect-5.1 P-10PSSect-5.1 P-11PSSect-5.1 P-12PSSect-5.1 P-13PSSect-5.1 P-14PSSect-5.1 P-15PSSect-5.1 P-16PSSect-5.1 P-17PSSect-5.1 P-18PSSect-5.1 P-19PSSect-5.1 P-20PSSect-5.1 P-21PSSect-5.1 P-22PSSect-5.1 P-23PSSect-5.1 P-24PSSect-5.1 P-25PSSect-5.1 P-26PSSect-5.1 P-27PSSect-5.1 P-28PSSect-5.1 P-29PSSect-5.1 P-30PSSect-5.1 P-31PSSect-5.1 P-32PSSect-5.1 P-33PSSect-5.1 P-34PSSect-5.1 P-35PSSect-5.1 P-36PSSect-5.1 P-37PSSect-5.1 P-38PSSect-5.1 P-39PSSect-5.1 P-40PSSect-5.1 P-41PSSect-5.1 P-42PSSect-5.1 P-43PSSect-5.1 P-44PSSect-5.1 P-45PSSect-5.1 P-46PSSect-5.1 P-47PSSect-5.1 P-48PSSect-5.1 P-49PSSect-5.1 P-50PSSect-5.1 P-51PSSect-5.1 P-52PSSect-5.1 P-53PSSect-5.1 P-54PSSect-5.1 P-55PSSect-5.1 P-56PSSect-5.1 P-57PSSect-5.1 P-58PSSect-5.1 P-59PSSect-5.1 P-60PSSect-5.1 P-61PSSect-5.1 P-62PSSect-5.1 P-63PSSect-5.1 P-64PSSect-5.1 P-65PSSect-5.1 P-66PSSect-5.1 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