   Chapter 5.5, Problem 14E ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343

#### Solutions

Chapter
Section ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343
Textbook Problem

# Evaluate the indefinite integral. ∫ y 2 ( 4 − y 3 ) 2 / 3 d y

To determine

To evaluate: The indefinite integral.

Explanation

Given:

The indefinite integral function is y2(4y3)23dy.

Calculation:

Consider u=4y3

Differentiate both sides of the equation.

du=3y2dydy=13y2du

The indefinite integral function is,

y2(4y3)23dy (1)

Substitute u for (4y3) and (13y2du) for dy in Equation (1)

y2(4y3)23dy=y2u23(13y2du)=(u23

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