   Chapter 5.5, Problem 15E ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343

#### Solutions

Chapter
Section ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343
Textbook Problem

# Evaluate the indefinite integral. ∫ cos 3 θ sin θ   d θ

To determine

To evaluate: The indefinite integral.

Explanation

Given:

The indefinite integral function is cos3θsinθdθ.

Calculation:

Consider u=cosθ

Differentiate both side of the Equation.

du=sinθdθdu=sinθdθ

The indefinite integral function is,

cos3θsinθdθ (1)

Substitute u for (cosθ) and (du) for (sinθdθ) in Equation (1)

cos3θsinθdθ=u3(du)=u3du (2)

Integrate Equation (2)

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