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Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

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BuyFindarrow_forward

Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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In Exercises 7-10, find the limit.

lim x 5 x 3 + 1 x 3 + x 2 + 4

To determine

To calculate: The value of the limit limx5x3+1x3+x2+4.

Explanation

Given Information:

The provided limit is limx5x3+1x3+x2+4.

Formula used:

Properties of limits;

limxaf(x)g(x)=limxaf(x)limxag(x)

limxa(f(x)±g(x))=limxaf(x)±limxag(x)

Special limits limx1x=0 and limx1x3=0

Calculation:

Consider the provided limit,

limx5x3+1x3+x2+4

Dividing the numerator and denominator throughout by x3

limx5x3+1x3x3+x2+4x3=limx5+1x31+1x+4x3

Applying the limit to both the numerator and denominator limxaf(x)g(x)=limxaf(x)limxag(x) using and then apply limxa(f(x)±g(x)

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