Chapter 5.6, Problem 11E

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Chapter
Section

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

# Given: D E ↔ ∥ B C , ¯ A D = a − 1 , D B = 2 a + 2 , A E = a , E C = 4 a − 5 Find: a  and  A D

To determine

To find:

Explanation

Given:

Theorem used:

If a line is parallel to one side of a triangle and intersects other two sides, then it divides these sides proportionally.

Calculation:

Given: DEâ†”âˆ¥BCÂ¯

Since if a line is parallel to one side of a triangle and intersects other two sides, then it divides these sides proportionally.

Thus aâˆ’12a+2=a4aâˆ’5.

Now let us find the value of a.

aâˆ’12a+2=a4aâˆ’5(aâˆ’1)(4aâˆ’5)=a(2</

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### f(x) = 3x3 x2 + 10; limxf(x); and limxf(x) x 1 5 10 100 1000 f(x) x 1 5 10 100 1000 f(x)

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

#### True or False: y = xex is a solution to y=y+yx.

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th