   Chapter 5.6, Problem 2E Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Solutions

Chapter
Section Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

Note: Exercises preceded by an asterisk are of a more challenging nature.In a chemical mixture, 2 g of chemical A are used for each gram of chemical B, and 3 g of chemical C are needed for each gram of B. If 72 g of the mixture are prepared, what amount (in grams) of each chemical in needed?

To determine

To find:

The amount of each chemical needed.

Explanation

Given:

In a chemical mixture, 2 g of chemical A are used for each gram of chemical B, and 3 g of chemical C are needed for each gram of B. In total 72 g of the mixture is prepared.

Calculation:

Let us assume that x g of chemical A, y g of chemical B and z g of chemical C are needed.

In total 72 g of the mixture is prepared.

x+y+z=72

Given that, 2 g of chemical A are used for each gram of chemical B, and 3 g of chemical C are needed for each gram of B.

x:y:z=2:1:3

Let x=2m,y=m,z=3m

Since we have x+y+z=72,

2m+m+3m=72

Now let us find the value of m.

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