   Chapter 5.6, Problem 9SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# In Exercises 7-10, find the limit. lim x → ∞ x − 7 x 2 + 1

To determine

To calculate: The value of the limit limxx7x2+1.

Explanation

Given Information:

The provided limit is limxx7x2+1.

Formula used:

Properties of limits;

limxaf(x)g(x)=limxaf(x)limxag(x)

limxa(f(x)±g(x))=limxaf(x)±limxag(x)

Special limits limx1x=0 and limx1x2=0

Calculation:

Consider the provided limit,

limxx7x2+1

Dividing the numerator and denominator throughout by x2

limxx7x2x2+1x2=limx1x7x21+1x2

Applying the limit to both the numerator and denominator using limxaf(x)g(x)=limxaf(x)limxag(x) and then apply limxa(f(

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