Chapter 5.CR, Problem 23CR

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Chapter
Section

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

# For Review Exercises 21 to 23, D E ¯ | | A C ¯ A D = 2 , A B = 10 , B E = 5 , A C = ?

To determine

To find:

The value of BC.

Explanation

Given:

DEÂ¯||ACÂ¯

Calculation:

First to show, Î”DBE similar to Î”ABC.

Since, corresponding angles are equal, then

âˆ BDE=âˆ BAC(âˆ´DEÂ¯||ACÂ¯)

âˆ BED=âˆ BCA(âˆ´DEÂ¯||ACÂ¯)

Here, Î”DBEÂ similarÂ toÂ Î”ABC

Let EC=x

Then,

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