   Chapter 5.CT, Problem 13CT Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Solutions

Chapter
Section Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

In △ M N P ,   N Q → bisects ∠ M N P . If PN = 6, MN = 9, and MP = 10, find PQ and QM. To determine

To find:

The value of PQ and QM.

Explanation

Given, MNP,

NQ bisects MNP.

PN = 6, MN = 9, and MP = 10,

By Angle-Bisector theorem:

If a ray bisects one angle of a triangle, then it divides the opposite side into segments whose length are proportional to the lengths of the two sides that form the bisected angle.

i.e. PQPN=QMMN

Let us take, PQ=x

MP=PQ+QM

QM=MP-PQ

QM=10-x

PN = 6, MN = 9, and MP = 10,

Substituting these values in the equation,

PQPN

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

In Exercises 7-12, solve for y in terms of x. (y3)2=5+(x+1)2

Calculus: An Applied Approach (MindTap Course List)

Year 2009 2010 2011 Sales, y 887 1028 1251 a. Plot the Cyber Monday sales (y) versus the year (t), where ...

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

Evaluate the integral. 49(x+1x)2dx

Calculus (MindTap Course List)

The absolute maximum value of f(x) = 6x − x2 on [1, 7] is: 3 9 76 −7

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th 