   # In the spectroscopic analysis of many substances, a series of standard solutions of known concentration are measured to generate a calibration curve. How would you prepare standard solutions containing 10.0, 25.0, 50.0, 75.0, and 100. ppm of copper from a commercially produced 1000.0-ppm solution? Assume each solution has a final volume of 100.0 mL. (See Exercise 123 for definitions.) ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 6, Problem 124CP
Textbook Problem
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## In the spectroscopic analysis of many substances, a series of standard solutions of known concentration are measured to generate a calibration curve. How would you prepare standard solutions containing 10.0, 25.0, 50.0, 75.0, and 100. ppm of copper from a commercially produced 1000.0-ppm solution? Assume each solution has a final volume of 100.0 mL. (See Exercise 123 for definitions.)

a)

Interpretation Introduction

Interpretation: The volume of stock solution of each sub-division has to be calculated.

Concept Introduction: Concentration of solution can be defined in terms of molarity as moles of solute to the volume of solution. The concentration of solution can be given by,

Molarity(inM)=Molesofsolute(ingrams)Volumeofsolution(inlitres)

Volumeofsolution(inlitres)=Molesofsolute(ingrams)Molarity(inM)

### Explanation of Solution

Record the given data

Mass of solute= 100ppm standard

Volume of stock solution= 1000ppm

The mass of the solute and volume of stock solution are recorded as shown above.

To calculate the volume of stock solution to make 100mLof100ppmsolution Cuinwater

100.µgCumL×100 mL=1×104µgCuneeded1×104

b)

Interpretation Introduction

Interpretation: The volume of stock solution of each sub-division has to be calculated.

Concept Introduction: Concentration of solution can be defined in terms of molarity as moles of solute to the volume of solution. The concentration of solution can be given by,

Molarity(inM)=Molesofsolute(ingrams)Volumeofsolution(inlitres)

Volumeofsolution(inlitres)=Molesofsolute(ingrams)Molarity(inM)

c)

Interpretation Introduction

Interpretation: The volume of stock solution of each sub-division has to be calculated.

Concept Introduction: Concentration of solution can be defined in terms of molarity as moles of solute to the volume of solution. The concentration of solution can be given by,

Molarity(inM)=Molesofsolute(ingrams)Volumeofsolution(inlitres)

Volumeofsolution(inlitres)=Molesofsolute(ingrams)Molarity(inM)

d)

Interpretation Introduction

Interpretation: The volume of stock solution of each sub-division has to be calculated.

Concept Introduction: Concentration of solution can be defined in terms of molarity as moles of solute to the volume of solution. The concentration of solution can be given by,

Molarity(inM)=Molesofsolute(ingrams)Volumeofsolution(inlitres)

Volumeofsolution(inlitres)=Molesofsolute(ingrams)Molarity(inM)

e)

Interpretation Introduction

Interpretation: The volume of stock solution of each sub-division has to be calculated.

Concept Introduction: Concentration of solution can be defined in terms of molarity as moles of solute to the volume of solution. The concentration of solution can be given by,

Molarity(inM)=Molesofsolute(ingrams)Volumeofsolution(inlitres)

Volumeofsolution(inlitres)=Molesofsolute(ingrams)Molarity(inM)

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