The vanadium in a sample of ore is converted to VO 2+ . The VO 2+ ion is subsequently titrated with MnO 4 − in acidic solution to form V(OH) 4 + and manganese(II) ion. The unbalanced titration reaction is M n O 4 − ( a q ) + V O 2 + + ( a q ) + H 2 O ( l ) → V ( O H ) 4 + ( a q ) + M n 2 + ( a q ) + H + ( a q ) To titrate the solution, 26.45 mL of 0.02250 M MnO 4 − was required. If the mass percent of vanadium in the ore was 58.1 %, what was the mass of the ore sample? Hint: Balance the titration reaction by the oxidation states method.

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Interpretation Introduction Interpretation: The mass of the ore sample has to be calculated. Concept Introduction: The mass of a compound can be calculated using the mass percentage of the compound to the given moles. It can be given by the equation, Mass of compound(in g)= Moles(in g) Mass percent(in %) Explanation Explanation To calculate the mass of ore sample To balance the reaction by oxidation state method. The chemical reaction can be given as, MnO 4 - ( aq ) +VO 2+ ( aq ) +H 2 O ( l ) → V(OH) 4 + ( aq ) +Mn 2+ ( aq ) +H + ( aq ) The oxidation states for various ions are, VO 2+ :O,-2 V,x+(-2)=+2 x=+4 MnO 4 - :O,-2 Mn,x+4(-2)=-1 x=+4 V(OH) 4 + :O,-2,H,+1 V,x+4(-2)+4+(+1)=+1 x=+5 Mn 2+ :Mn,+2 The oxidation state of vanadium increases from +4 to +5 in V(OH) 4 + . The oxidation state of manganese decreases from +7 to +2 in Mn 2+ . Thus balancing the equation, we get MnO 4 - ( aq ) +5VO 2+ ( aq ) +11H 2 O ( l ) → 5V(OH) 4 + ( aq ) +Mn 2+ ( aq ) +22H + ( aq ) The unbalanced chemical equation is balanced with the help of oxidation method. It was found that the oxidation state of vanadium increases in V(OH) 4 + and oxidation state of manganese decreases in Mn 2+

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Chemistry: An Atoms First Approach

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Chemistry: An Atoms First Approach

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Steven S. Zumdahl + 1 other

Publisher: Cengage Learning

ISBN: 9781305079243

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Interpretation Introduction

Interpretation:

The mass of the ore sample has to be calculated.

Concept Introduction:

The mass of a compound can be calculated using the mass percentage of the compound to the given moles. It can be given by the equation,

Mass of compound(in g)= Moles(in g)Mass percent(in %)

Explanation of Solution

Explanation

To calculate the mass of ore sample

To balance the reaction by oxidation state method.

The chemical reaction can be given as,

MnO4-(aq)+VO2+(aq)+H2O(l)→V(OH)4+(aq)+Mn2+(aq)+H+(aq)

The oxidation states for various ions are,

VO2+:O,-2V,x+(-2)=+2x=+4

MnO4-:O,-2Mn,x+4(-2)=-1x=+4

V(OH)4+:O,-2,H,+1V,x+4(-2)+4+(+1)=+1x=+5

Mn2+:Mn,+2

The oxidation state of vanadium increases from +4 to +5 in V(OH)4+.

The oxidation state of manganese decreases from +7 to +2 in Mn2+.

Thus balancing the equation, we get

MnO4-(aq)+5VO2+(aq)+11H2O(l)→5V(OH)4+(aq)+Mn2+(aq)+22H+(aq)

The unbalanced chemical equation is balanced with the help of oxidation method. It was found that the oxidation state of vanadium increases in V(OH)4+ and oxidation state of manganese decreases in Mn2+

Chemistry: An Atoms First Approach

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Chemistry: An Atoms First Approach

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