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Three students were asked to find the identity of the metal in a particular sulfate salt. They dissolved a 0.14 72-g sample of the salt in water and treated it with excess barium chloride, resulting in the precipitation of barium sulfate. After the precipitate had been filtered and dried, it weighed 0.2327 g. Each student analyzed the data independently and came to different conclusions. Pat decided that the metal was titanium. Chris thought it was sodium. Randy reported that it was gallium. What formula did each student assign to the sulfate salt? Look for information on the sulfates of gallium, sodium, and titanium in this text and reference books such as the CRC Handbook of Chemistry and Physics. What further tests would you suggest to determine which student is most likely correct?

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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Section
BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 6, Problem 146MP
Textbook Problem
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Three students were asked to find the identity of the metal in a particular sulfate salt. They dissolved a 0.14 72-g sample of the salt in water and treated it with excess barium chloride, resulting in the precipitation of barium sulfate. After the precipitate had been filtered and dried, it weighed 0.2327 g.

Each student analyzed the data independently and came to different conclusions. Pat decided that the metal was titanium. Chris thought it was sodium. Randy reported that it was gallium. What formula did each student assign to the sulfate salt?

Look for information on the sulfates of gallium, sodium, and titanium in this text and reference books such as the CRC Handbook of Chemistry and Physics. What further tests would you suggest to determine which student is most likely correct?

a)

Interpretation Introduction

Interpretation: The formula of the sulphate salt assigned by each student has to be identified.

Concept Introduction: When two soluble solutions are mixed together, an insoluble salt formation occurs called as precipitate. These precipitates fall out of the solution and the reactions are called as precipitation reaction.

Explanation of Solution

Given:

Record the given info

Weight of the sample = 0.1742g

Weight of the precipitate = 0.2327g

The weight of the sample and weight of the precipitate are recorded as shown above.

To calculate the moles of BaSO4

Molecular mass of BaSO4 = 233.4g

Moles of BaSO4 = 0.23271mol233.4g=9.970×10-4molBaSO4

The moles of BaSO4 depends on the formula of the sulphate salt

The general equation can be given as,

Mx(SO4)y(aq)+yBa2+(aq)yBaSO4(s)+xMz+

The mole ratio between the unknown sulphates salt and BaSO4 shows variation depending upon the value of y .

The moles of BaSO4 is calculated by plugging in the values of molar mass of BaSO4 to the weight of the precipitate. The moles of BaSO4 is found to be 9.970×10-4mol

To write the formula of sulphate salt assigned by Pat

Pat thinks that formula of sulphate salt is TiSO4

Then the equation becomes,

TiSO4(aq)+Ba2+(aq)BaSO4(s)+Ti2+(aq)

There is 1:1 mole ratio between BaSO4 and TiSO4 , therefore 9.970×10-4mol of TiSO4 is needed.

Assuming the molar mass of TiSO4 ,

MolarmassofTiSO4=0.1472g9.970×10-4mol=147.6g/mol

The value of calculated molar mass of TiSO4 is compared with the standard molar mass of TiSO4 using the atomic masses in the periodic table.

The standard molar mass of TiSO4 = 143.95g/mol

On comparing the standard molar mass and calculated molar mass of TiSO4 , the Titanium sulphate assigned by Pat seems to be reasonable.

The formula assigned by Pat is Titanium sulphate. The molar mass of Titanium sulphate is calculated using the weight of the sample and the moles of BaSO4 . The standard molar mass of TiSO4 is calculated using the standard atomic masses from the periodic table. On comparing both the standard and calculated molar mass of TiSO4 the formula of sulphate salt given by Pat seems to be reasonable.

To write the formula of sulphate salt assigned by Chris

Chris thinks that formula of sulphate salt is Na2SO4

The equation becomes,

Na2SO4(aq)+Ba2+(aq)BaSO(s)+2Na+(aq)

There is 1:1 mole ratio between BaSO4 and Na2SO4 , therefore 9

b)

Interpretation Introduction

Interpretation: the most likely correct salt of sulphate has to be given.

Concept Introduction: When two soluble solutions are mixed together, an insoluble salt formation occurs called as precipitate. These precipitates fall out of the solution and the reactions are called as precipitation reaction.

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Chapter 6 Solutions

Chemistry: An Atoms First Approach
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