   Chapter 6, Problem 14P

Chapter
Section
Textbook Problem

A 65.0-kg basketball player jumps vertically and leaves the floor with a velocity of 1.80 m/s upward, (a) What impulse does the player experience? (b) What force does the floor exert on the player before the jump? (c) What is the total average force exerted by the floor on the player if the player is in contact with the floor for 0.450 s during the jump?

(a)

To determine
The impulse that the basketball player experiences.

Explanation

Given Info:

The mass of the basketball player is 65.0kg .

The velocity of the player when he leaves the ground is 1.80m/s .

Consider the upward direction as positive.

Formula to calculate the impulse that the basketball player experiences,

I=m((vfvi))

• vf is the final velocity of the basketball player
• vi is the initial velocity of the basketball player
• m is the mass of the basketball player

Substitute 65.0kg for m , 1

(b)

To determine
The force exerted on the player by the floor before the jump.

(c)

To determine
The total average force exerted by the floor on the player if the player is in contact with the floor for 0.450s during the jump.

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