BuyFind

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
BuyFind

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

Solutions

Chapter 6, Problem 14PS

(a)

Interpretation Introduction

Interpretation: The region of lines in emission spectrum of neon has to be identified.

Concept introduction:

  • Electromagnetic radiations are a type of energy surrounding us. They are of different types like radio waves, IR, UV, X-ray etc.
  • Infrared radiation in the wavelength of 700nm to 1mm

(b)

Interpretation Introduction

Interpretation: Any of the given lines is whether found in the emission spectrum of neon in figure 6.6 has to be determined.

Concept introduction:

  • Electromagnetic radiations are a type of energy surrounding us. They are of different types like radio waves, IR, UV, X-ray etc.
  • Emission spectrum: It is a spectrum of a compound due to the electromagnetic radiation emitted when the transition of an atom or molecule from the higher to lower state.

(c)

Interpretation Introduction

Interpretation: The most energetic line among the given lines in the emission spectrum of neon has to be identified.

Concept introduction:

  • Planck’s equation,

  E==hcλwhere, E=energyh=Planck'sconstantν=frequency

The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

  • The frequency of the light is inversely proportional to its wavelength.

  ν=cλwhere, c=speedoflightν=frequencyλ=wavelength

(d)

Interpretation Introduction

Interpretation: The frequency and the energy per photon of most energetic line in the emission spectrum of neon have to be identified.

Concept introduction:

  • Planck’s equation,

  E==hcλwhere, E=energyh=Planck'sconstantν=frequency

The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

  • The frequency of the light is inversely proportional to its wavelength.

ν=cλwhere, c=speedoflightν=frequencyλ=wavelength

Want to see the full answer?

Check out a sample textbook solution.

Want to see this answer and more?

Experts are waiting 24/7 to provide step-by-step solutions in as fast as 30 minutes!*

*Response times may vary by subject and question complexity. Median response time is 34 minutes for paid subscribers and may be longer for promotional offers.