   Chapter 6, Problem 1TYS ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# In Exercises 1–3, use integration by parts to find the indefinite integral. ∫ x e x + 1   d x

To determine

To calculate: The indefinite integral xex+1dx with the help of integration by parts.

Explanation

Given Information:

The integral is xex+1dx.

Formula used:

The integration by part of two differentiable function is,

udv=uvvdu

The basic rule of integration for constant C is,

Cdx=0

The integration of exponential is,

exdx=ex+C

Calculation:

Consider the provided integral, xex+1dx.

Since, the integrand of the provided indefinite integral is xex+1 which is made up of two function.

Let the first function is x,

u=x

Differentiate both side with respect to x.

du=dx

Let the second function ex+1

dv=ex+1

Integrate both side with respect to x, use the formula for the exponential integration

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