   Chapter 6, Problem 23P

Chapter
Section
Textbook Problem

A 45.0-kg girl is standing on a 150.-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.50 m/s to the right relative to the plank. (a) What is her velocity relative to the surface of the ice? (b) What is the velocity of the plank relative to the surface of the ice?

(a)

To determine
Velocity of the girl relative to the ice.

Explanation

Given Info: Mass of girl is mG=45.0kg , Mass of plank is  mP=15.0kg , Initial velocity of the girl and plank is vGIandvPI=0 and velocity of girl relative to plank  is vGP=1.50 m/s

Explanation:

The expression for velocity is

vGI=vGP+vPI

• vGI is the Velocity of the girl relative to the ice
• vGP is the Velocity of the girl relative to the Plank
• vPI is the Velocity of the Plank relative to the ice

Apply conservation of momentum to girl – plank system

(mGvGI+mPvPI)i=(mGvGI+mPvPI)f

• mG is the mass of the girl.
• mP is the mass of the plank

(b)

To determine
Velocity of the Plank relative to Ice.

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