(a)
Interpretation: The given following terms has to be differentiated.
Concept introduction:
Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in
Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.
Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.
Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.
In your equation,
(b)
Interpretation: The given following terms has to be differentiated.
Concept introduction:
Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.
Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.
Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.
Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.
In your equation,
(c)
Interpretation: The given following terms has to be differentiated.
Concept introduction:
Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.
Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.
Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.
Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.
In your equation,
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Chemistry: An Atoms First Approach
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- Consider four beakers. Beaker A has an aqueous solution of NaOH in which the OH- ions are represented by blue circles. Beaker B has a weak acid; HX is represented by red circles. Beaker C has a weak acid; H2X is represented by green circles. Beaker D has a weak acid; H3X is represented by yellow circles. X- ions are represented by triangles. Match the pictorial representations with the reactions given below. (a) HX(aq)+OH(aq) X(aq)+H2O(b) H2X(aq)+2OH(aq) X(aq)+2H2O(c) H3X(aq)+3OH(aq) X(aq)+3H2Oarrow_forwardChromium has been investigated as a coating for steel cans. The thickness of the chromium film is determined by dissolving a sample of a can in acid and oxidizing the resulting Cr3+ to Cr2O72 with the peroxydisulfate ion: S2O82(aq) + Cr3+(aq) + H2O(l) Cr2O72(aq) + SO42(aq) + H+(aq) (Unbalanced) After removal of unreacted S2O82 an excess of ferrous ammonium sulfate [Fe(NH4)2(SO4)26H2O] is added, reacting with Cr2O72 produced from the first reaction. The unreacted Fe2+ from the excess ferrous ammonium sulfate is titrated with a separate K2Cr2O7 solution. The reaction is: H+(aq) + Fe2+(aq) + Cr2O72(aq) Fe3+(aq) + Cr3+(aq) + H2O(l) (Unbalanced) a. Write balanced chemical equations for the two reactions. b. In one analysis, a 40.0-cm2 sample of a chromium-plated can was treated according to this procedure. After dissolution and removal of excess S2O82, 3.000 g of Fe(NH4)2(SO4)26H2O was added. It took 8.58 mL of 0.0520 M K2Cr2O7 solution to completely react with the excess Fe2+. Calculate the thickness of the chromium film on the can. (The density of chromium is 7.19 g/cm3)arrow_forward
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