   Chapter 6, Problem 26RE ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Using Integration Tables In Exercises 23-30, use the integration table in Appendix C to find the indefinite integral. ∫ x 2 x 2 − 6 d x

To determine

To calculate: The solution of indefinite integral x2x26dx.

Explanation

Given Information:

The provided expression is,

x2x26dx

Formula used:

The integral formula,

u2u2±a2du=12(uu2±a2a2ln|u+u2±a2|)+C

General power differentiation Rule:

ddx[un]=nun1dudx

Calculation:

Consider the provided expression,

x2x26dx

Let u=x

Differentiate u=x with respect to x by the use of power rule of differentiation.

du=dx

Consider the provided expression

x2x26dx

And rewrite it as.

x2x26dx=x2x2(61/2)2dx

Now, compare it with the expression u2u2a2du

Here, a=61/2, u=x and du=dx

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