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Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

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Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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Using Integration Tables In Exercises 23–30, use the integration table in Appendix C to find the indefinite integral.

1 4 x 2 49 d x

To determine

To calculate: The value of indefinite integral 14x249dx.

Explanation

Given Information:

The provided expression is,

14x249dx

Formula used:

The integral formula,

1u2a2du=12aln|uau+a|+C

General power differentiation Rule:

ddx[un]=nun1dudx

Calculation:

Consider the provided expression,

14x249dx

Let, u=2x

Differentiate u=2x with respect to x by the use of power rule of differentiation.

du=2dx

Consider the provided expression,

14x249dx

And rewrite as.

14x249dx=1(2x)272dx

Now compare it with the formula,

1u2a2du

Here, a=7, u=2x and du=2dx.

Multiply and divide the integral by 2

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