   Chapter 6, Problem 28RE ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Using Integration Tables In Exercises 23–30, use the integration table in Appendix C to find the indefinite integral. ∫ ( ln   3 x ) 2   d x

To determine

To calculate: The value of indefinite integral (ln3x)2dx.

Explanation

Given Information:

The provided expression is:

(ln3x)2dx

Formula used:

The integral formula,

(lnu)2du=u[22lnu+(lnu)2]+C

General power differentiation Rule:

ddx[un]=nun1dudx

Calculation:

Consider the provided expression,

(ln3x)2dx

Let, u=3x

Differentiate u=3x with respect to x by the use of power rule of differentiation.

du=3dx

Consider the provided expression:

(ln3x)2dx

Multiply and divide by 3.

(ln3x)2dx=13(ln3x)23dx

Substitute u for 3x, and du for 3dx

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