   # Calculate the concentration of all ions present in each of the following solutions of strong electrolytes. a. 0.0200 mole of sodium phosphate in 10.0 mL of solution b. 0.300 mole of barium nitrate in 600.0 mL of solution c. 1.00 g of potassium chloride in 0.500 L of solution d. 132 g of ammonium sulfate in 1.50 L of solution ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 6, Problem 32E
Textbook Problem
6 views

## Calculate the concentration of all ions present in each of the following solutions of strong electrolytes.a. 0.0200 mole of sodium phosphate in 10.0 mL of solutionb. 0.300 mole of barium nitrate in 600.0 mL of solutionc. 1.00 g of potassium chloride in 0.500 L of solutiond. 132 g of ammonium sulfate in 1.50 L of solution

a)

Interpretation Introduction

Interpretation: The concentration of ions in the solution has to be calculated.

Concept Introduction: Concentration can be defined in terms of molarity as moles of solute per volume of solution in litres. It can be given by the expression,

Molarity(inM)=massofsolute(in g)volumeofsolution(inL)

### Explanation of Solution

Record the given data

Moles of Sodium phosphate= 0.200moles

Volume of the solution= 10.0mL

Calculation for the concentration of separate ions is as follows,

The balanced equation for dissolving ions,

Na3PO4(s)3Na+(aq)+PO43-(aq)

The molarity of ions can be calculated by the formula,

Molarity=massofsolutevolumeofsolution

Therefore, by substituting the given info in the formula, the concentrations of separate ions can be given as,

Molarity=0.02000.0100=2

b)

Interpretation Introduction

Interpretation: The concentration of ions in the solution has to be calculated.

Concept Introduction: Concentration can be defined in terms of molarity as moles of solute per volume of solution in litres. It can be given by the expression,

Molarity(inM)=massofsolute(in g)volumeofsolution(inL)

c)

Interpretation Introduction

Interpretation: The concentration of ions in the solution has to be calculated.

Concept Introduction: Concentration can be defined in terms of molarity as moles of solute per volume of solution in litres. It can be given by the expression,

Molarity(inM)=massofsolute(in g)volumeofsolution(inL)

d)

Interpretation Introduction

Interpretation: The concentration of ions in the solution has to be calculated.

Concept Introduction: Concentration can be defined in terms of molarity as moles of solute per volume of solution in litres. It can be given by the expression,

Molarity(inM)=massofsolute(in g)volumeofsolution(inL)

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts
Which of the following is not one of the ways fats are useful in foods? Fats contribute to the taste and smell ...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

No animal cell has a ___________. a. plasma membrane b. flagellum c. lysosome d. cell wall

Biology: The Unity and Diversity of Life (MindTap Course List)

Make the following temperature conversions:

Chemistry & Chemical Reactivity

How do Newton’s laws lead you to conclude that gravitation has to be universal?

Horizons: Exploring the Universe (MindTap Course List)

For the circuit shown in Figure P28.55. the ideal voltmeter reads 6.00 V and the ideal ammeter reads 3.00-k. Fi...

Physics for Scientists and Engineers, Technology Update (No access codes included) 