   Chapter 6, Problem 35P

Chapter
Section
Textbook Problem

A railroad car of mass 2.00 × 104 kg moving at 3.00 m/s collides and couples with two coupled railroad cars, each of the same mass as the single car and moving in the same direction at 1.20 m/s. (a) What is the speed of the three coupled cars after the collision? (b) How much kinetic energy is lost, in the collision?

(a)

To determine
Speed of the three coupled car.

Explanation

Given Info: Mass of the single car is m1=2.00×104kg , mass of the coupled car is m2=4.00×104kg , mass of all the three coupled cars is m3=6.00×104kg , velocity of the single car is v1=3.00m/s and velocity of the coupled car is v2=1.20m/s

Explanation:

Apply the law of conservation of momentum to coupled cars –three coupled cars

(m1v1+m2v2)i=(m3v3)f (1)

• m1 is the mass of the single car.
• m2 is the mass of the coupled car.
• m3 is the mass of all the three coupled car.
• v1 is the velocity of the single car.
• v2 is the velocity of the coupled car.

Substitute 2.00×104kg for m1 , 4

(b)

To determine
Loss of kinetic energy.

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