   Chapter 6, Problem 4P

Chapter
Section
Textbook Problem

A 0.280-kg volleyball approaches a player horizontally with a speed of 15.0 m/s. The player strikes the ball with her fist and causes the ball to move in the opposite direction with a speed of 22.0 m/s. (a) What impulse is delivered to the ball by the player? (b) If the player's fist is in contact with the hall for 0.060 0 s, find the magnitude of the average force exerted on the player’s fist.

(a)

To determine
The impulse delivered to the ball by the player.

Explanation

Given info: The mass of the volleyball is 0.280kg , the speed of the player is 15.0m/s , and the speed of the ball moves in the opposite direction is 22.0m/s .

The expression for the impulse delivered to the ball.

I=Δp . (I)

• Δp is the change in momentum
• I is the impulse

Rewrite the expression (I) in terms of mass and velocity.

I=m(vfvi)

• m is the mass of the ball
• vf is the final velocity of the ball
• vi is the initial velocity of the ball

Substitute 0.280kg for m, 22

(b)

To determine
The magnitude of the average force exerted on the player’s fist.

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