   Chapter 6, Problem 51P

Chapter
Section
Textbook Problem

A 2.00 × 1O3-kg car moving cast at 10.0 m/s collides with a 3.00 × 103-kg car moving north. The cars stick together and move as a unit after the collision, at an angle of 40.0° north of east and a speed of 5.22 m/s. Find the speed and direction of the 3.00 × 103-kg car before the collision.

To determine
Initial speed and direction of 3.00 ×103 kg car.

Explanation

Given Info: Mass of the car 1 is m1=2.00×103 kg , mass of the car 2 is m2=3.00×103kg , initial velocity of car1towards east is v1=10.0 m/s , final velocity of combination of both car is vf=5.22 m/s Take eastward as +xaxis and northward as +yaxis Set the initial xmomentum as 0 .

Explanation:

Apply conservation of momentum in ydirection .

0+(m2v2)i=(m1+m2)vfsinθ (1)

• m1 is the mass of the car1.
• m2 is the  mass of the car 2.
• v2i is the initial velocity of the car2.
• vf is the final velocity of combination of both car
• θ is the angle by which both car moves together after collision

Substitute 3.00×103kg for m2 , 2

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