   Chapter 6, Problem 6.13P Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939

Solutions

Chapter
Section Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939
Textbook Problem

The relative compaction of a silty sand in the field is 94%. Given that γd(max) = 17 kN/m3 and γd(min) = 13.8 kN/m3, determine the dry unit weight in the field and the relative density of compaction.

To determine

Find the dry unit weight in the field and relative density of compaction.

Explanation

Given information:

The relative compaction of silty sand (R) is 94 %.

The maximum dry unit weight of the silty sand γdmax is 17kN/m3.

The minimum dry unit weight of the silty sand γdmin is 13.8kN/m3.

Calculation:

Determine the field dry unit weight (γd(field)) using the relation.

R=[γd(field)γd(max)]

Substitute 94 % for R and 17kN/m3 for γd(max).

94100=[γd(field)17]0.94×17=γd(field)γd(field)=15.98kN/m3

Therefore, the dry unit weight in the field is 15.98kN/m3_.

Determine the relative density of compaction using the relation

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