   Chapter 6, Problem 6.3P Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939

Solutions

Chapter
Section Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939
Textbook Problem

Calculate the zero-air-void unit weights (lb/ft3) for a soil with Gs = 2.66 at moisture contents of 7, 11, 15, 19, and 23%.

To determine

Find the zero–air–void unit weights for a soil at different moisture contents.

Explanation

Given information:

The specific gravity of soil Gs is 2.66.

The various water contents of the soil (w) are 7 %, 11 %, 15 %, 19 %, and 23 %.

Calculation:

Determine zero–air–void unit weight for a soil at 7 % moisture content using the relation.

γzav=Gsγw1+Gsw

Here, γw is the unit weight of water.

Substitute 2.66 for Gs, 62.4lb/ft3 for γw, and 7 % for w.

γzav=2.66×62.41+2.66×7100=139.9lb/ft3

Therefore, the zero–air–void unit weight for a soil at 7 % moisture content is 139.9lb/ft3_.

Determine zero–air–void unit weight for a soil at 11 % moisture content using the relation.

γzav=Gsγw1+Gsw

Substitute 2.66 for Gs, 62.4lb/ft3 for γw, and 11 % for w.

γzav=2.66×62.41+2.66×11100=128.4lb/ft3

Therefore, the zero–air–void unit weight for a soil at 11 % moisture content is 128.4lb/ft3_.

Determine zero–air–void unit weight for a soil at 15 % moisture content using the relation.

γzav=Gsγw1+Gsw

Substitute 2.66 for Gs, 62.4lb/ft3 for γw, and 15 % for w

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