General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
7th Edition
ISBN: 9781285853918
Author: H. Stephen Stoker
Publisher: Cengage Learning
Question
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Chapter 6, Problem 6.49EP

(a)

Interpretation Introduction

Interpretation:

The chemical equation Na+H2ONaOH+H2 has to be balanced.

Concept Introduction:

Statement that uses chemical symbols and formulas instead of words in order to describe the changes that takes place in a chemical reaction is known as chemical equation.  Reactants are the substances that are present in starting of the chemical reaction and it is entered in left side of the chemical equation.  Products are the substance that is obtained from the reactants as a final outcome of the chemical reaction and it is entered in right side of the chemical equation.  In order to write a chemical equation four conventions are used and they are,

  • Correct formulas of the reactants are written in left side of chemical equation.
  • Correct formulas of products are written in right side of chemical equation.
  • An arrow is placed between reactants and products which point towards the products.
  • If two or more substances are present in reactant and product, plus sign is used to separate them.

Balanced chemical equation is the one that has equal number of atoms of each element that is involved in the chemical reaction on both sides of the chemical equation.  An unbalanced chemical equation can be balanced by adding coefficients to the equation.  It is a number that is placed in left side of the chemical formula so that it changes the amount only and not the identity.

(a)

Expert Solution
Check Mark

Answer to Problem 6.49EP

The balanced chemical equation is 2Na+2H2O2NaOH+H2.

Explanation of Solution

Given chemical equation is Na+H2ONaOH+H2.  Looking into the equation, the element that is occurring only once on both sides and the compound that has greater number of atoms has to be started with.  All the atoms except hydrogen is balanced in the given chemical equation.  So start with balancing hydrogen atom.

Balancing H atoms:  There are two H atoms on left side and three H atoms on the right side of the chemical equation.  Placing the coefficient 2 in front of H2O in the left side and coefficient 2 in front of NaOH balances the H atom on both sides.  This makes the sodium atom to be unbalanced.

Na+2H2O2NaOH+H2

Balancing Na atoms:  After balancing the H atom, the total number of Na atoms on the right side is 2 and on left side is 1.  Hence, adding coefficient 2 to Na atom on the left side balances the Na atom on both sides.

2Na+2H2O2NaOH+H2

The number of atoms of each element on both sides have to be checked and it can be given as shown below,

Atom Leftside Rightside_Na 2x1=2 2x1=2H 2x2=4 2+2=4O 2x1=2 2x1=2_

As there are same number of atoms of each element on both sides of the equation, it is said to be a balanced chemical equation.  The balanced chemical equation can be given as,

2Na+2H2O2NaOH+H2

Conclusion

Given chemical equation is balanced.

(b)

Interpretation Introduction

Interpretation:

The chemical equation Na+ZnSO4Na2SO4+Zn has to be balanced.

Concept Introduction:

Statement that uses chemical symbols and formulas instead of words in order to describe the changes that takes place in a chemical reaction is known as chemical equation.  Reactants are the substances that are present in starting of the chemical reaction and it is entered in left side of the chemical equation.  Products are the substance that is obtained from the reactants as a final outcome of the chemical reaction and it is entered in right side of the chemical equation.  In order to write a chemical equation four conventions are used and they are,

  • Correct formulas of the reactants are written in left side of chemical equation.
  • Correct formulas of products are written in right side of chemical equation.
  • An arrow is placed between reactants and products which point towards the products.
  • If two or more substances are present in reactant and product, plus sign is used to separate them.

Balanced chemical equation is the one that has equal number of atoms of each element that is involved in the chemical reaction on both sides of the chemical equation.  An unbalanced chemical equation can be balanced by adding coefficients to the equation.  It is a number that is placed in left side of the chemical formula so that it changes the amount only and not the identity.

(b)

Expert Solution
Check Mark

Answer to Problem 6.49EP

The balanced chemical equation is 2Na+ZnSO4Na2SO4+Zn.

Explanation of Solution

Given chemical equation is Na+ZnSO4Na2SO4+Zn.  Looking into the equation, the element that is occurring only once on both sides and the compound that has greater number of atoms has to be started with.  All the atoms except sodium is balanced in the given chemical equation.  So start with balancing sodium atom.

Balancing Na atoms:  There are two Na atoms on right side and one Na atom on the left side of the chemical equation.  Placing the coefficient 2 in front of Na in the left side balances the Na atom on both sides.

2Na+ZnSO4Na2SO4+Zn

The number of atoms of each element on both sides have to be checked and it can be given as shown below,

Atom Leftside Rightside_Na 2x1=2 1x2=2Zn 1x1=1 1x1=1S 1x1=1 1x1=1O 1x4=4 1x4=4_

As there are same number of atoms of each element on both sides of the equation, it is said to be a balanced chemical equation.  The balanced chemical equation can be given as,

2Na+ZnSO4Na2SO4+Zn

Conclusion

Given chemical equation is balanced.

(c)

Interpretation Introduction

Interpretation:

The chemical equation NaBr+Cl2NaCl+Br2 has to be balanced.

Concept Introduction:

Statement that uses chemical symbols and formulas instead of words in order to describe the changes that takes place in a chemical reaction is known as chemical equation.  Reactants are the substances that are present in starting of the chemical reaction and it is entered in left side of the chemical equation.  Products are the substance that is obtained from the reactants as a final outcome of the chemical reaction and it is entered in right side of the chemical equation.  In order to write a chemical equation four conventions are used and they are,

  • Correct formulas of the reactants are written in left side of chemical equation.
  • Correct formulas of products are written in right side of chemical equation.
  • An arrow is placed between reactants and products which point towards the products.
  • If two or more substances are present in reactant and product, plus sign is used to separate them.

Balanced chemical equation is the one that has equal number of atoms of each element that is involved in the chemical reaction on both sides of the chemical equation.  An unbalanced chemical equation can be balanced by adding coefficients to the equation.  It is a number that is placed in left side of the chemical formula so that it changes the amount only and not the identity.

(c)

Expert Solution
Check Mark

Answer to Problem 6.49EP

The balanced chemical equation is 2NaBr+Cl22NaCl+Br2.

Explanation of Solution

Given chemical equation is NaBr+Cl2NaCl+Br2.  Looking into the equation, the element that is occurring only once on both sides and the compound that has greater number of atoms has to be started with.  Starting with balancing chlorine atom,.

Balancing Cl atoms:  There are two Cl atoms on left side and one Cl atom on the right side of the chemical equation.  Placing the coefficient 2 in front of NaCl in the right side balances the Cl atom on both sides.  This leaves Na atoms to become unbalanced.

NaBr+Cl22NaCl+Br2

Balancing Na atoms:  There are one Na atom on left side and two Na atoms on the right side of the chemical equation.  Placing the coefficient 2 in front of NaBr in the left side balances the Na atom on both sides.  This leaves all the atoms on both sides to be balanced.

2NaBr+Cl22NaCl+Br2

The number of atoms of each element on both sides have to be checked and it can be given as shown below,

Atom Leftside Rightside_Na 2x1=2 2x1=2Br 2x1=2 1x2=2Cl 1x2=2 2x1=2_

As there are same number of atoms of each element on both sides of the equation, it is said to be a balanced chemical equation.  The balanced chemical equation can be given as,

2NaBr+Cl22NaCl+Br2

Conclusion

Given chemical equation is balanced.

(d)

Interpretation Introduction

Interpretation:

The chemical equation ZnS+O2ZnO+SO2 has to be balanced.

Concept Introduction:

Statement that uses chemical symbols and formulas instead of words in order to describe the changes that takes place in a chemical reaction is known as chemical equation.  Reactants are the substances that are present in starting of the chemical reaction and it is entered in left side of the chemical equation.  Products are the substance that is obtained from the reactants as a final outcome of the chemical reaction and it is entered in right side of the chemical equation.  In order to write a chemical equation four conventions are used and they are,

  • Correct formulas of the reactants are written in left side of chemical equation.
  • Correct formulas of products are written in right side of chemical equation.
  • An arrow is placed between reactants and products which point towards the products.
  • If two or more substances are present in reactant and product, plus sign is used to separate them.

Balanced chemical equation is the one that has equal number of atoms of each element that is involved in the chemical reaction on both sides of the chemical equation.  An unbalanced chemical equation can be balanced by adding coefficients to the equation.  It is a number that is placed in left side of the chemical formula so that it changes the amount only and not the identity.

(d)

Expert Solution
Check Mark

Answer to Problem 6.49EP

The balanced chemical equation is 2ZnS+3O22ZnO+2SO2.

Explanation of Solution

Given chemical equation is ZnS+O2ZnO+SO2.  Looking into the equation, the element that is occurring only once on both sides and the compound that has greater number of atoms has to be started with.  Starting with balancing oxygen atom.

Balancing O atoms:  There are two O atoms on left side and three O atoms on the right side of the chemical equation.  Placing the coefficient 3 in front of O2 in the left side, coefficient 2 in front of both ZnO and SO2 on right side, balances the O atoms on both sides.  This leaves Zn and S atoms to become unbalanced.

ZnS+3O22ZnO+2SO2

Balancing Zn atoms:  There are one Zn atom on left side and two Zn atoms on the right side of the chemical equation.  Placing the coefficient 2 in front of ZnS in the left side balances the Zn atom on both sides.  This leaves all the atoms on both sides to be balanced.

2ZnS+3O22ZnO+2SO2

The number of atoms of each element on both sides have to be checked and it can be given as shown below,

Atom Leftside Rightside_Zn 2x1=2 2x1=2S 2x1=2 1x2=2O 3x2=6 2+4=6_

As there are same number of atoms of each element on both sides of the equation, it is said to be a balanced chemical equation.  The balanced chemical equation can be given as,

2ZnS+3O22ZnO+2SO2

Conclusion

Given chemical equation is balanced.

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Chapter 6 Solutions

General, Organic, and Biological Chemistry

Ch. 6.3 - Prob. 4QQCh. 6.3 - Prob. 5QQCh. 6.4 - Prob. 1QQCh. 6.4 - Prob. 2QQCh. 6.4 - Prob. 3QQCh. 6.4 - Prob. 4QQCh. 6.5 - Prob. 1QQCh. 6.5 - Prob. 2QQCh. 6.5 - Prob. 3QQCh. 6.5 - Prob. 4QQCh. 6.6 - Prob. 1QQCh. 6.6 - Prob. 2QQCh. 6.6 - Prob. 3QQCh. 6.6 - Prob. 4QQCh. 6.6 - Prob. 5QQCh. 6.7 - Prob. 1QQCh. 6.7 - Prob. 2QQCh. 6.7 - Prob. 3QQCh. 6.7 - Prob. 4QQCh. 6.8 - The problem How many grams of O2 are needed to...Ch. 6.8 - Prob. 2QQCh. 6.8 - How many conversion factors are needed in solving...Ch. 6.8 - Which of the following is the correct conversion...Ch. 6.9 - Prob. 1QQCh. 6.9 - Prob. 2QQCh. 6.9 - Prob. 3QQCh. 6.9 - Prob. 4QQCh. 6 - Calculate, to two decimal places, the formula mass...Ch. 6 - Calculate, to two decimal places, the formula mass...Ch. 6 - The compound 1-propanethiol, which is the eye...Ch. 6 - A compound associated with the odor of garlic on a...Ch. 6 - Indicate the number of objects present in each of...Ch. 6 - Indicate the number of objects present in each of...Ch. 6 - A sample is found to contain 0.500 mole of a...Ch. 6 - A sample is found to contain 0.800 mole of a...Ch. 6 - Select the quantity that contains the greater...Ch. 6 - Select the quantity that contains the greater...Ch. 6 - What is the mass, in grams, of 1.000 mole of each...Ch. 6 - What is the mass, in grams, of 1.000 mole of each...Ch. 6 - How much, in grams, does each of the following...Ch. 6 - How much, in grams, does each of the following...Ch. 6 - How many moles of specified particles are present...Ch. 6 - How many moles of specified particles are present...Ch. 6 - What is the formula mass of a compound whose molar...Ch. 6 - What is the formula mass of a compound whose molar...Ch. 6 - The mass of 7.00 moles of a compound is determined...Ch. 6 - The mass of 5.00 moles of a compound is determined...Ch. 6 - How many moles of oxygen atoms are present in...Ch. 6 - How many moles of nitrogen atoms are present in...Ch. 6 - How many total moles of atoms are present in each...Ch. 6 - Prob. 6.24EPCh. 6 - Write the six mole-to-mole conversion factors that...Ch. 6 - Write the six mole-to-mole conversion factors that...Ch. 6 - Prob. 6.27EPCh. 6 - Based on the chemical formula H2CO3, write the...Ch. 6 - Determine the number of atoms present in 20.0 g...Ch. 6 - Determine the number of atoms present in 30.0 g...Ch. 6 - Determine the mass, in grams, of each of the...Ch. 6 - Determine the mass, in grams, of each of the...Ch. 6 - Determine the number of moles of substance present...Ch. 6 - Determine the number of moles of substance present...Ch. 6 - Determine the number of atoms of sulfur present in...Ch. 6 - Determine the number of atoms of nitrogen present...Ch. 6 - Determine the number of grams of sulfur present in...Ch. 6 - Determine the number of grams of oxygen present in...Ch. 6 - Prob. 6.39EPCh. 6 - Prob. 6.40EPCh. 6 - A compound has a molar mass of 34.02 g. What is...Ch. 6 - A compound has a molar mass of 32.06 g. What is...Ch. 6 - Indicate whether each of the following chemical...Ch. 6 - Indicate whether each of the following chemical...Ch. 6 - Prob. 6.45EPCh. 6 - How many total atoms does each of the following...Ch. 6 - How many oxygen atoms are present on the reactant...Ch. 6 - How many oxygen atoms are present on the reactant...Ch. 6 - Prob. 6.49EPCh. 6 - Balance the following chemical equations. a. H2S +...Ch. 6 - Prob. 6.51EPCh. 6 - Balance the following chemical equations. a. C2H4...Ch. 6 - Prob. 6.53EPCh. 6 - After the following chemical equation was...Ch. 6 - The following diagrams represent the reaction of...Ch. 6 - The following diagrams represent the reaction of...Ch. 6 - Prob. 6.57EPCh. 6 - Prob. 6.58EPCh. 6 - Write the six mole-to-mole conversion factors that...Ch. 6 - Prob. 6.60EPCh. 6 - For the chemical reaction Sb2S3+6HCl2SbCl3+3H2S...Ch. 6 - For the chemical reaction UF6+2H2OUO2F2+4HF write...Ch. 6 - Using each of the following balanced chemical...Ch. 6 - Using each of the following balanced chemical...Ch. 6 - For the chemical reaction C6H12O6+6O26CO2+6H2O how...Ch. 6 - For the chemical reaction C3H8O2+4O23CO2+4H2O how...Ch. 6 - How many water molecules (H2O) are needed to react...Ch. 6 - How many carbon monoxide molecules (CO) are needed...Ch. 6 - The following diagram represents the...Ch. 6 - The following diagram represents the...Ch. 6 - How many moles of beryllium (Be) are needed to...Ch. 6 - How many moles of magnesium (Mg) are needed to...Ch. 6 - The principal constituent of natural gas is...Ch. 6 - Tungsten (W) metal, which is used to make...Ch. 6 - The catalytic converter that is standard equipment...Ch. 6 - A mixture of hydrazine (N2H4) and hydrogen...Ch. 6 - Both water and sulfur dioxide are products from...Ch. 6 - Potassium thiosulfate (K2S2O3) is used to remove...Ch. 6 - How many grams of beryllium (Be) are needed to...Ch. 6 - How many grams of aluminum (Al) are needed to...Ch. 6 - The theoretical yield of product for a particular...Ch. 6 - The theoretical yield of product for a particular...Ch. 6 - Prob. 6.83EPCh. 6 - In an experiment designed to produce calcium oxide...Ch. 6 - If 125.5 g of Ca3N2 were produced from 29.0 g of...Ch. 6 - If 64.15 g of HCl were produced from 2.07 g of H2...
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