The most energetic line among the given lines in the emission spectrum of chromium has to be identified. Concept introduction: Planck’s equation, E = hν = hc λ where, E = energy h = Planck's constant ν = frequency The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases. The frequency of the light is inversely proportional to its wavelength. ν = c λ where, c = speed of light ν = frequency λ = wavelength

BuyFind

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
BuyFind

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

Solutions

Chapter 6, Problem 66GQ

(a)

Interpretation Introduction

Interpretation: The most energetic line among the given lines in the emission spectrum of chromium has to be identified.

Concept introduction:

  • Planck’s equation,

    E==hcλwhere, E=energyh=Planck'sconstantν=frequency

The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

  • The frequency of the light is inversely proportional to its wavelength.

  ν=cλwhere, c=speedoflightν=frequencyλ=wavelength

(b)

Interpretation Introduction

Interpretation: The colour of line having wavelength 425.4nm has to be identified.

Concept introduction:

  • Electromagnetic radiations are a type of energy surrounding us. They are of different types like radio waves, IR, UV, X-ray etc.
  • Visible light lies in the wavelength of 400nm to 700nm

Chemistry & Chemical Reactivity, Chapter 6, Problem 66GQ

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