Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 6, Problem 6.7P
To determine
Find the hydraulic conductivity of the clay specimen (k) and the quantity of water collected using the constant head permeability test (Q).
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A falling-head permeability test was carried out on a clay soil of diameter 100 mm and length150 mm. In 4 minutes the head in the standpipe of diameter 5mm dropped from 680 to 350mm. Calculate the hydraulic conductivity of this clay.
A double drain consolidation test was performed on a sample of marine clay. The thickness of the clay layer is 50mm and the hydraulic conductivity during the test was 1,753x10-8 m/min. During the test the following data were determined.
σ '1= 300 KN/m2 e= 0.42
σ '2= 500 KN/m2 e=0.30
Determine: The time to reach 75% consolidation The excess water pressure value after 50 min of starting the test at 10 mm depth
A falling-head permeability test was carried out on a clay soil of diameter 10 cm and length 15 cm. In 1 hour the head in the standpipe of diameter 5 mm dropped from 68 cm to 50.2 cm. Calculate the hydraulic conductivity of this clay.
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Fundamentals of Geotechnical Engineering (MindTap Course List)
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- Determine the hydraulic conductivity of Soil A using the data obtained from the constant head test and the hydraulic conductivity of Soil B using the data obtained from the falling head test.arrow_forwardFor a variable head permeability test, these values are given:• Length of the soil specimen 200 mm• Area of the soil specimen 1000 mm2• Area of the standpipe 40 mm2• Head difference at time t 0 is 500 mm• Head difference at time t 3 min is 300 mma. Determine the hydraulic conductivity of the soil in cm/sec.b. What was the head difference at time t 100 sec?arrow_forwardA constant-head test was conducted on a sample of soil 15 cm long and 60 cm2 in cross-sectional area. The quantity of water collected was 50cm3 in 20 seconds under a head difference of 24 cm. Calculate the hydraulic conductivity. If the porosity of the sand is 55%, calculate the average velocity and the seepage velocity. Estimate the’ hydraulic conductivity of a similar soil with a porosity of 35% from the results of this test.arrow_forward
- In a constant-head permeability test, a sample of soil 12 cm long and 6 cm in diameter discharged 1.5 x 10^(-3) m^3 of water in 10 minutes. The head difference in two piezometers A and B located at 1 cm and 11 cm, respectively, from the bottom of the sample is 2 cm. Determine the hydraulic conductivity of the soil. What is the soil type tested?arrow_forwardFor a falling head permeability test, these valueare given: Length of the soil specimen = 200 mm Area of the soil specimen = 1000 mm2 Area of the standpipe = 40 mm2 Head difference at time, t = 0 min is 500 mm Head difference at time, t = 3 min is 300 mm1. Determine the hydraulic conductivity of thesoil in cm/sec.2. What was the head difference at time, t =100 sec?arrow_forwardA constant head permeability test was carried out on a sample of sand. The diameter and the length of the sample were 10 and 20 cm. respectively. The head of water was maintained at 35 cm. If 110 cm3 of water is collected in 80 seconds, compute the hydraulic conductivity of the sand.arrow_forward
- For a falling head laboratory test, the following are the given values:• Length of soil specimen = 210.00 mm• Initial head = 523.00 mm• Final head = 297.00 mm• Duration of test = 3.50 mins• Area of standpipe = 42.0 sq.mm• Area of specimen = 1050.00 sq.mmA. Compute for the hydraulic conductivity of the soil in cm/sec.B. Determine the seepage velocity if n=0.35C. Determine the head difference at t = 120 secarrow_forwardA constant head permeability test was carried out on a cylindrical sample of sand 10 cm diameter and 15 cm height. 160 cm³ of water was collected in 31.75 sec under a head of 30 cm. 1. Compute the coefficient of permeability in cm/s. 2. Compute the velocity of flow in m/s.arrow_forwardFor a normally consolidated laboratory clay specimen drained on both sides, the following are given: σ0’ = 4000 ib/ft² e=1.2 σ0’ + Δσ’= 5000 lb/ft² e=0.9 Thickness of clay specimen= 2in Time for 50% consolidation= 2 min. Determine the hydraulic conductivity (ft/min) of the clay for the loading range. How long (in days) will it take for a 6-ft clay layer in the field(drained on both side) To reach 60% consolidation?arrow_forward
- For a laboratory consolidation test on a clay specimen (drained on both sides) the following results were obtained: Thickness of clay soil= 25 mm; P_1 = 50 kPa; P_2 = 120 kPa; e_1 = 0.92; e_2 = 0.78; Time for 50% consolidation= 2.5 min. Tv = 0.197. Determine the hydraulic conductivity of the clay for the loading range in m/min. Show diagramarrow_forwardThe following data are for a falling-head permeability test:• Length of the soil sample = 140 mm• Diameter of soil sample = 70 mm• Area of the standpipe = 19.6 mm2• At time t = 0, head difference = 500 mm• At time t = 7 min, head difference = 350 mma. Determine the hydraulic conductivity of the soil (cm/sec)b. What was the head difference at t = 5 min?arrow_forwardThe data from a falling-head test on a silty clay are: Cross sectional area of soil = 1000 mm^2 Length of soil sample = 200 mm Area of stand pipe = 40 mm^2 Head difference at time t = 0 is 500 mm Head difference at time t = 3 min is 300 mm a) Determine the hydraulic conductivity of the soil in cm/sec. b) What is the head difference at time t = 100 sec in mmarrow_forward
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