General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
7th Edition
ISBN: 9781285853918
Author: H. Stephen Stoker
Publisher: Cengage Learning
Question
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Chapter 6, Problem 6.83EP

(a)

Interpretation Introduction

Interpretation:

Theoretical yield of SO2 has to be given for the chemical reaction where sulfur dioxide is produced from sulfur and oxygen where, 9.75g of SO2 is only obtained out of the possible 11.2g.

Concept Introduction:

In a chemical reaction, when the reactants gives product, the amount of product formed from the given amount of reactant can be said in terms of yield.

Theoretical yield of a chemical reaction is the maximum amount of the product that can be obtained from the given amount of reactants provided there is no loss or inefficiencies occur.  The actual yield of the chemical reaction is the experimental yield that is obtained.  Actual yield of the product is always lesser than the theoretical yield.  For this, there are two reasons.  They are,

  • In mechanical process, some of the product is lost.  Mechanical process involves the transfer of materials from a container to another container.
  • Unwanted side reactions occur in the actual chemical reaction due to impurities present.  These are not considered in theoretical yield.

Actual yield is the amount of product that is got from a chemical reaction.  The actual yield has to be measured and not calculated.

Percent yield is the term that is used to tell about the product loss.  It is the ratio of the actual amount of product that is obtained in a chemical reaction to the theoretical yield multiplied by 100 to give percent.  Mathematical equation for percent yield is given as,

  Percentyield = Actual yieldTheoretical yieldx100

(b)

Interpretation Introduction

Interpretation:

Actual yield of SO2 has to be given for the chemical reaction where sulfur dioxide is produced from sulfur and oxygen where, 9.75g of SO2 is only obtained out of the possible 11.2g.

Concept Introduction:

In a chemical reaction, when the reactants gives product, the amount of product formed from the given amount of reactant can be said in terms of yield.

Theoretical yield of a chemical reaction is the maximum amount of the product that can be obtained from the given amount of reactants provided there is no loss or inefficiencies occur.  The actual yield of the chemical reaction is the experimental yield that is obtained.  Actual yield of the product is always lesser than the theoretical yield.  For this, there are two reasons.  They are,

  • In mechanical process, some of the product is lost.  Mechanical process involves the transfer of materials from a container to another container.
  • Unwanted side reactions occur in the actual chemical reaction due to impurities present.  These are not considered in theoretical yield.

Actual yield is the amount of product that is got from a chemical reaction.  The actual yield has to be measured and not calculated.

Percent yield is the term that is used to tell about the product loss.  It is the ratio of the actual amount of product that is obtained in a chemical reaction to the theoretical yield multiplied by 100 to give percent.  Mathematical equation for percent yield is given as,

  Percentyield = Actual yieldTheoretical yieldx100

(c)

Interpretation Introduction

Interpretation:

Percent yield of SO2 has to be given for the chemical reaction where sulfur dioxide is produced from sulfur and oxygen where, 9.75g of SO2 is only obtained out of the possible 11.2g.

Concept Introduction:

In a chemical reaction, when the reactants gives product, the amount of product formed from the given amount of reactant can be said in terms of yield.

Theoretical yield of a chemical reaction is the maximum amount of the product that can be obtained from the given amount of reactants provided there is no loss or inefficiencies occur.  The actual yield of the chemical reaction is the experimental yield that is obtained.  Actual yield of the product is always lesser than the theoretical yield.  For this, there are two reasons.  They are,

  • In mechanical process, some of the product is lost.  Mechanical process involves the transfer of materials from a container to another container.
  • Unwanted side reactions occur in the actual chemical reaction due to impurities present.  These are not considered in theoretical yield.

Actual yield is the amount of product that is got from a chemical reaction.  The actual yield has to be measured and not calculated.

Percent yield is the term that is used to tell about the product loss.  It is the ratio of the actual amount of product that is obtained in a chemical reaction to the theoretical yield multiplied by 100 to give percent.  Mathematical equation for percent yield is given as,

  Percentyield = Actual yieldTheoretical yieldx100

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Chapter 6 Solutions

General, Organic, and Biological Chemistry

Ch. 6.3 - Prob. 4QQCh. 6.3 - Prob. 5QQCh. 6.4 - Prob. 1QQCh. 6.4 - Prob. 2QQCh. 6.4 - Prob. 3QQCh. 6.4 - Prob. 4QQCh. 6.5 - Prob. 1QQCh. 6.5 - Prob. 2QQCh. 6.5 - Prob. 3QQCh. 6.5 - Prob. 4QQCh. 6.6 - Prob. 1QQCh. 6.6 - Prob. 2QQCh. 6.6 - Prob. 3QQCh. 6.6 - Prob. 4QQCh. 6.6 - Prob. 5QQCh. 6.7 - Prob. 1QQCh. 6.7 - Prob. 2QQCh. 6.7 - Prob. 3QQCh. 6.7 - Prob. 4QQCh. 6.8 - The problem How many grams of O2 are needed to...Ch. 6.8 - Prob. 2QQCh. 6.8 - How many conversion factors are needed in solving...Ch. 6.8 - Which of the following is the correct conversion...Ch. 6.9 - Prob. 1QQCh. 6.9 - Prob. 2QQCh. 6.9 - Prob. 3QQCh. 6.9 - Prob. 4QQCh. 6 - Calculate, to two decimal places, the formula mass...Ch. 6 - Calculate, to two decimal places, the formula mass...Ch. 6 - The compound 1-propanethiol, which is the eye...Ch. 6 - A compound associated with the odor of garlic on a...Ch. 6 - Indicate the number of objects present in each of...Ch. 6 - Indicate the number of objects present in each of...Ch. 6 - A sample is found to contain 0.500 mole of a...Ch. 6 - A sample is found to contain 0.800 mole of a...Ch. 6 - Select the quantity that contains the greater...Ch. 6 - Select the quantity that contains the greater...Ch. 6 - What is the mass, in grams, of 1.000 mole of each...Ch. 6 - What is the mass, in grams, of 1.000 mole of each...Ch. 6 - How much, in grams, does each of the following...Ch. 6 - How much, in grams, does each of the following...Ch. 6 - How many moles of specified particles are present...Ch. 6 - How many moles of specified particles are present...Ch. 6 - What is the formula mass of a compound whose molar...Ch. 6 - What is the formula mass of a compound whose molar...Ch. 6 - The mass of 7.00 moles of a compound is determined...Ch. 6 - The mass of 5.00 moles of a compound is determined...Ch. 6 - How many moles of oxygen atoms are present in...Ch. 6 - How many moles of nitrogen atoms are present in...Ch. 6 - How many total moles of atoms are present in each...Ch. 6 - Prob. 6.24EPCh. 6 - Write the six mole-to-mole conversion factors that...Ch. 6 - Write the six mole-to-mole conversion factors that...Ch. 6 - Prob. 6.27EPCh. 6 - Based on the chemical formula H2CO3, write the...Ch. 6 - Determine the number of atoms present in 20.0 g...Ch. 6 - Determine the number of atoms present in 30.0 g...Ch. 6 - Determine the mass, in grams, of each of the...Ch. 6 - Determine the mass, in grams, of each of the...Ch. 6 - Determine the number of moles of substance present...Ch. 6 - Determine the number of moles of substance present...Ch. 6 - Determine the number of atoms of sulfur present in...Ch. 6 - Determine the number of atoms of nitrogen present...Ch. 6 - Determine the number of grams of sulfur present in...Ch. 6 - Determine the number of grams of oxygen present in...Ch. 6 - Prob. 6.39EPCh. 6 - Prob. 6.40EPCh. 6 - A compound has a molar mass of 34.02 g. What is...Ch. 6 - A compound has a molar mass of 32.06 g. What is...Ch. 6 - Indicate whether each of the following chemical...Ch. 6 - Indicate whether each of the following chemical...Ch. 6 - Prob. 6.45EPCh. 6 - How many total atoms does each of the following...Ch. 6 - How many oxygen atoms are present on the reactant...Ch. 6 - How many oxygen atoms are present on the reactant...Ch. 6 - Prob. 6.49EPCh. 6 - Balance the following chemical equations. a. H2S +...Ch. 6 - Prob. 6.51EPCh. 6 - Balance the following chemical equations. a. C2H4...Ch. 6 - Prob. 6.53EPCh. 6 - After the following chemical equation was...Ch. 6 - The following diagrams represent the reaction of...Ch. 6 - The following diagrams represent the reaction of...Ch. 6 - Prob. 6.57EPCh. 6 - Prob. 6.58EPCh. 6 - Write the six mole-to-mole conversion factors that...Ch. 6 - Prob. 6.60EPCh. 6 - For the chemical reaction Sb2S3+6HCl2SbCl3+3H2S...Ch. 6 - For the chemical reaction UF6+2H2OUO2F2+4HF write...Ch. 6 - Using each of the following balanced chemical...Ch. 6 - Using each of the following balanced chemical...Ch. 6 - For the chemical reaction C6H12O6+6O26CO2+6H2O how...Ch. 6 - For the chemical reaction C3H8O2+4O23CO2+4H2O how...Ch. 6 - How many water molecules (H2O) are needed to react...Ch. 6 - How many carbon monoxide molecules (CO) are needed...Ch. 6 - The following diagram represents the...Ch. 6 - The following diagram represents the...Ch. 6 - How many moles of beryllium (Be) are needed to...Ch. 6 - How many moles of magnesium (Mg) are needed to...Ch. 6 - The principal constituent of natural gas is...Ch. 6 - Tungsten (W) metal, which is used to make...Ch. 6 - The catalytic converter that is standard equipment...Ch. 6 - A mixture of hydrazine (N2H4) and hydrogen...Ch. 6 - Both water and sulfur dioxide are products from...Ch. 6 - Potassium thiosulfate (K2S2O3) is used to remove...Ch. 6 - How many grams of beryllium (Be) are needed to...Ch. 6 - How many grams of aluminum (Al) are needed to...Ch. 6 - The theoretical yield of product for a particular...Ch. 6 - The theoretical yield of product for a particular...Ch. 6 - Prob. 6.83EPCh. 6 - In an experiment designed to produce calcium oxide...Ch. 6 - If 125.5 g of Ca3N2 were produced from 29.0 g of...Ch. 6 - If 64.15 g of HCl were produced from 2.07 g of H2...
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