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ChemistryPrinciples of Instrumental Analysis(a) Interpretation: The maximum kinetic energy of an ejected photoelectron from cesium when irradiated by 520 nm light should be calculated. Concept introduction: Data given: Longest wavelength of radiation needed to eject photoelectrons from cesium = λ min = 660 nm Formulae to use: Energy involved in photoelectric effect is expressed as, E λ = KE m + ω E λ = energy of the incident radiation KE m = kinetic energy of the ejected electrons ω = work function (minimum energy needed to eject the electrons) E = h ν Where, E = energy of light h = Plank’s constant = 6.6254 × 10 − 34 Js ν = frequency of light For air or vacuum, ν = c λ Where, c = velocity of light in vacuum (3.00 × 10 8 m/s ) λ = wavelength of lightStart your trial now! First week only $4.99!*arrow_forward*

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7th Edition

Douglas A. Skoog + 2 others

Publisher: Cengage Learning

ISBN: 9781305577213

Chapter 6, Problem 6.9QAP

Interpretation Introduction

**(a)**

**Interpretation:**

The maximum kinetic energy of an ejected photoelectron from cesium when irradiated by

**Concept introduction:**

Data given:

Longest wavelength of radiation needed to eject photoelectrons from cesium =

Formulae to use:

Energy involved in photoelectric effect is expressed as,

Where,

E = energy of light

h = Plank’s constant =

For air or vacuum,

Where,

c = velocity of light in vacuum (3.00

Interpretation Introduction

**(b)**

**Interpretation:**

Velocity of the photoelectrons ejected when cesium is irradiated with

**Concept introduction:**

Data:

Rest mass of an electron

Formulae to use:

m = mass

v = velocity