# The wavelength of the light at the point 2000 c m − 1 has to be determined Concept introduction: The frequency of the light is inversely proportional to its wavelength. ν = c λ where, c = speed of light ν = frequency λ = wavelength Wavelength and wavenumber are inversely proportional to each other. W a v e l e n g t h = 1 w a v e n u m b e r Planck’s equation, E = hν where, E = energy h = Planck's constant ν = frequency The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter 6, Problem 73IL

(a)

Interpretation Introduction

## Interpretation: The wavelength of the light at the point 2000 cm−1 has to be determinedConcept introduction: The frequency of the light is inversely proportional to its wavelength.  ν = cλwhere, c = speed of lightν = frequencyλ = wavelength Wavelength and wavenumber are inversely proportional to each other.  Wavelength = 1wavenumber Planck’s equation,  E = hν where, E = energyh = Planck's constantν = frequencyThe energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

Explanation

(b)

Interpretation Introduction

### Interpretation: The high energy and low energy end of spectrum has to be determined.Concept introduction: Wavelength and wavenumber are inversely proportional to each other.  Wavelength = 1wavenumber Planck’s equation,  E = hν = hcλwhere, E = energyh = Planck's constantν = frequencyThe energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

(c)

Interpretation Introduction

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