   # A 10.00-mL sample of vinegar, an aqueous solution of acetic acid (HC 2 H 3 O 2 ), is titrated with 0.5062 M NaOH, and 16.58 mL is required to reach the equivalence point. a. What is the molarity of the acetic acid? b. If the density of the vinegar is 1.006 g/cm 3 , what is the mass percent of acetic acid in the vinegar? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 6, Problem 76E
Textbook Problem
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## A 10.00-mL sample of vinegar, an aqueous solution of acetic acid (HC2H3O2), is titrated with 0.5062 M NaOH, and 16.58 mL is required to reach the equivalence point.a. What is the molarity of the acetic acid?b. If the density of the vinegar is 1.006 g/cm3, what is the mass percent of acetic acid in the vinegar?

a)

Interpretation Introduction

Interpretation:

To calculate the molarity of acetic acid in vinegar

Concept Introduction: Concentration can be defined in terms of molarity as moles of solute per volume of solution in litres. It can be given by the expression,

Molarity=massofsolutevolumeofsolution

### Explanation of Solution

Given info:

Molarity of sodium hydroxide=0.5062M

Volume of sodium hydroxide=16.58mL

Volume of acetic acid in vinegar=10.00mL

Molarity of acetic acid in vinegar=?

The molarity of acetic acid in vinegar can be calculated from volume and molarity of sodium hydroxide along with the volume of acetic acid in vinegar.

The chemical equation can be written as,

HC3H3O2+NaOHHC2H3O2+H2O

Moles of acetic acid= 16.58mLofNaOH×0.5062mmolNaOH1mLNaOH×1mmolHC3H3O21mmolNaOH

=8

(b)

Interpretation Introduction

Interpretation:

To calculate the mass percentage of acetic acid in vinegar.

Concept introduction: Mass percentage is one of the ways to represent the concentration of an element or compound in a mixture. Mass percentages can be defined as the mass of the sample divided by the total mass.

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