   Chapter 6.1, Problem 25E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Finding an Indefinite Integral In Exercises 17-38, find the indefinite integral. (Hint: Integration by parts is not required for all the integrals.) ∫ e 1 / t t 2 d t

To determine

To calculate: The value of indefinite integral e1tt2dt.

Explanation

Given Information:

The provided indefinite integral is e1tt2dt.

Formula used:

Integration Property:

eaxdx=eaxa+C

Calculation:

Consider the indefinite integral e1tt2dt

Here,

u=1t

Differentiate both side with respect t;

ddt(u)=ddt(1t)=(1t2)

And,

du=(1t2)dt

Now,

The indefinite integral e1tt2dt becomes,

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