   Chapter 6.1, Problem 29E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Finding an Indefinite Integral In Exercises 17-38, find the indefinite integral. (Hint: Integration by parts is not required for all the integrals.) ∫ ( ln   x ) 2 x d x

To determine

To calculate: The value of indefinite integral (lnx)2xdx.

Explanation

Given Information:

The provided indefinite integral is (lnx)2xdx.

Formula used:

Integration Property:

tndt=tn+1n+1,n1

Calculation:

Consider the indefinite integral (lnx)2xdx

Here,

u=lnx

Differentiate both sides with respect x;

ddx(u)=ddx(lnx)=(1x)

And,

du=(1x)dx

Now,

The indefinite integral (lnx)2xdx becomes,

(lnx)2<

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