   # Let R be the set of all real number. Is a partition of R? Explain your answer. ### Discrete Mathematics With Applicat...

5th Edition
EPP + 1 other
Publisher: Cengage Learning,
ISBN: 9781337694193

#### Solutions

Chapter
Section ### Discrete Mathematics With Applicat...

5th Edition
EPP + 1 other
Publisher: Cengage Learning,
ISBN: 9781337694193
Chapter 6.1, Problem 29ES
Textbook Problem
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## Let R be the set of all real number. Is a partition of R? Explain your answer.

To determine

### Explanation of Solution

Given information:

{R+,R{0}}

Concept used:

R be the set of all real numbers.

Calculation:

Let R be the set of all real numbers.

Define the set R+ is the set which contains all the positive real numbers and the set R contains all the negative real numbers.

The objective is to check that the set {R+,R{0}} is partition of real number set R.

Partition of the set:

Let the set {A1,A2,......,An} be the subsets of A. The set {A1,A2,......,An} is said to be partition of A, if each the elements are mutually disjoint and A1A2.....An=A.

Check that whether the set {R+,R{0}} is mutually disjoint set or not.

By the definition of the sets R+ and R there are no common elements in both the sets R+ and R

Thus, R+R=

By the definition of the set R+ the set does not contain the element 0

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