   Chapter 6.1, Problem 55E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# Using Formulas In Exercises 55-58, find the integral by using the appropriate formula from Exercises 53 and 54. ∫ x 2 e 5 x d x

To determine

To calculate: The value of the integral x2e5xdx.

Explanation

Given Information:

The integral x2e5xdx

Formula used:

From question 54, xneaxdx=xneaxanaxn1eaxdx for n>0

Calculation:

Consider the provided integral,

x2e5xdx

With n=2and a=5, use formula from question 54, xneaxdx=xneaxanaxn1eaxdx for n>0 to solve the integral

x2e5xdx=x2e5x525x21e5xdx=x2e5x525xe5xdx

Now again applying xneaxdx

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