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Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

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BuyFindarrow_forward

Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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In Exercises 9-14, use the integration table in Appendix C to find the indefinite integral.

x 2 81 x 2 d x

To determine

To calculate: The solution of indefinite integral x281x2dx.

Explanation

Given Information:

The expression is provided as, x281x2dx.

Formula used:

The formula for integral u2±a2u2du is,

u2±a2u2du=u2±a2u+ln|u+u2±a2|+C

Calculation:

Let u=x.

Differentiate the above equation with respect to x,

du=dx

Consider the provided expression,

x281x2dx

Rewrite.

x281x2dx=x292x2dx

Here, a=9, u=x and du=dx.

Substitute u for x, a for 9, and du for dx

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