   Chapter 6.2, Problem 13QY ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# In Exercises 9-14, use the integration table in Appendix C to find the indefinite integral. ∫ 2 x 1 + e 4 x 2 d x

To determine

To calculate: The solution of indefinite integral 2x1+e4x2dx.

Explanation

Given Information:

The expression is provided as,

2x1+e4x2dx

Formula used:

The formula for integral 11+eudu is,

11+eudu=uln(1+eu)+C

Calculation:

Let u=4x2.

Differentiate above function with respect to x,

du=4(2x)dx=8xdx

Consider the provided expression:

2x1+e4x2dx

Divide and multiply by 4.

2x1+e4x2dx=148x1+e4x2dx=1411+e4x28xdx

Substitute u for 4x2, and du for 8xdx

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