   Chapter 6.2, Problem 16E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Using Integration Tables In Exercises 9–36, use the integration table in Appendix C to find the indefinite integral. See Examples 1, 2,3, and 5. ∫ ( ln   5 x ) 2   d x

To determine

To calculate: The solution of indefinite integral (ln5x)2dx.

Explanation

Given Information:

The integral is provided as, (ln5x)2dx.

Formula used:

The formula 44 for integral (lnu)2du is,

(lnu)2du=u[22lnu+(lnu)2]+C

Calculation:

Let u=5x.

Differentiate o0n both side with respect to x,

du=5dx

Consider the provided integral,

(ln5x)2dx

Multiply and divide by 5.

(ln5x)2dx=15(ln5x)25dx

Substitute u for 5x, and du for 5dx

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