   Chapter 6.2, Problem 20E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Using Integration Tables In Exercises 9–36, use the integration table in Appendix C to find the indefinite integral. See Examples 1, 2,3, and 5. ∫ t 2 2 + 9 t 2   d t

To determine

To calculate: The solution of indefinite integral t22+9t2dt.

Explanation

Given Information:

The expression is provided as, t22+9t2dt.

Formula used:

The integral formula is,

u2u2±a2du=18[u(2u2±a2)u2±a2a4ln|u+u2±a2|]+C(1001)

Calculation:

Let u=3t.

Differentiate the above function on both side with respect to x,

du=3dt

Consider the provided expression,

t22+9t2dt

Multiply and divide by 27.

t22+9t2dt=12727t22+9t2dt

Rewrite.

t22+9t2dt=127(3t)2(21/2)2+(3t)23dt

Here, a=21/2, u=3t and du=3dt.

Substitute u for 3t, a for 21/2, and du for 3dt

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