   Chapter 6.2, Problem 2CP ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Checkpoint 2Use the integration table in Appendix C to find ∫ x 2 + 16 x   d x .

To determine

To calculate: The value of indefinite integral x2+16xdx.

Explanation

Given Information:

The integral is provided as:

x2+16xdx

Formula used:

(1) The formula 25 for integral u2+a2udu is:

u2+a2udu=u2+a2aln|a+u2+a2u|+C

(2) General power differentiation Rule:

ddx[un]=nun1dudx

Calculation:

Consider u=x.

Differentiate the considered function with respect to x using power rule of differentiation.

du=dx

Consider the provided integral:

x2+16xdx

Rewrite.

x2+16xdx=x2+42xdx

Here, a=4, u=x and du=dx.

Substitute u for x, a for 4, and du for dx

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