   # Which has the greater energy per photon. UV-B light at 310 nm or microwave radiation having a frequency of 2.45 GHz (1 GHz = 10 9 s -1 )? (a) UVB (b) microwave ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 6.2, Problem 2RC
Textbook Problem
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## Which has the greater energy per photon. UV-B light at 310 nm or microwave radiation having a frequency of 2.45 GHz (1 GHz = 109 s-1)? (a) UVB (b) microwave

Interpretation Introduction

Interpretation: The radiation having the greater energy per photon from the given types of electromagnetic radiations is to be determined from the given option.

Concept introduction:

• Electromagnetic radiations are a type of energy surrounding us. They are of different types like radio waves, IR, UV, X-ray etc.
• UV-B lies between 315nm to 280nm whereas microwave radiation is in between 30cm and 1mm .
• Planck’s equation,

E=where, E=energyh=Planck'sconstantν=frequency

The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

• The frequency of the light is inversely proportional to its wavelength.

ν=cλwhere, c=speedoflightν=frequencyλ=wavelength

### Explanation of Solution

Reason for correct option

The frequency of microwave radiation is 2.45GHz=2.45 ×109Hz=2.45 ×109s1

The speed of light,c=2.998×108m/s

The wavelength of Microwave radiation is calculated by using the equation,

λ=cν=2.998×108m/s2.45 ×109s1=0

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