   Chapter 6.2, Problem 3QY ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# In Exercises 1–6, use integration by parts to find the indefinite integral. ∫ ( x + 1 )   ln   x   d x

To determine

To calculate: The solution of indefinite integral (x+1)lnxdx using integration by parts.

Explanation

Given Information:

The provided expression is, lnx3dx.

Formula used:

The formula for integration by parts is,

udv=uvvdu

Here, u and v be the differentiable functions x.

General Power Integral Rule:

undu=un+1n+1+C

Calculation:

Consider the provided expression,

(x+1)lnxdx

Let u=lnx and dv=(x+1)dx. So,

du=1xdx

And,

v=(x+1)dx=x22+x

Apply integration by parts to solve integral of (x+1)lnxdx

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