   Chapter 6.2, Problem 41E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Using Integration Tables In Exercises 37– 44, use the integration table in Appendix C to evaluate the definite integral. See Example 4. ∫ 0 4 6 1 + e 0.5 x   d x

To determine

To calculate: The solution of definite integral 0461+e0.5xdx.

Explanation

Given Information:

The provided definite integral is,

0461+e0.5xdx

Formula used:

The formula for integral 11+enudu is;

11+enudu=u1nln(1+enu)+C

Here, n is the any number.

The general power differentiation Rule:

ddx[un]=nun1dudx

Calculation:

Consider u=x.

Differentiate the considered function with respect to x using power rule of differentiation.

du=dx

Consider the provided expression:

0461+e0.5xdx

Rewrite.

0461+e0.5xdx=60411+e0.5xdx

Here, n=0.5, u=x and du=dx.

Substitute u for x, n for 0.50 and du for dx.

0461+e0.5xdx=60411+enudu

Use the above formula of integration and solve the above integral as;

0461+e0

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